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Project ID:
1003107302
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Je daná postupnosť \( \left( \frac{\sqrt2}4\left( \sqrt2 -1 \right)^n \right)^{\infty}_{n=1} \). Rekurentné vyjadrenie tejto postupnosti je:
\( a_1=\frac{\sqrt2}4\left(\sqrt2-1\right);\ a_{n+1}=a_n\left(\sqrt2-1\right),\ n\in\mathbb{N} \)
\( a_1=\frac{\sqrt2}4;\ a_{n+1}=a_n\left(\sqrt2-1\right),\ n\in\mathbb{N} \)
\( a_1=\sqrt2-1\,;\ a_{n+1}=a_n\left(\sqrt2-1\right),\ n\in\mathbb{N} \)
\( a_1=\frac{\sqrt2}4\left(\sqrt2-1\right);\ a_{n+1}=a_n\left(\sqrt2-1\right)^2,\ n\in\mathbb{N} \)