1003107302 | math4u.vsb.cz

SubArea:

Introduction to sequences

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Project ID:

1003107302

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1

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0

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We are given the sequence

{(\frac{\sqrt{2}}{4} {(\sqrt{2} - 1)}^{n})}_{n = 1}^{\infty}

. Find the recursive formula of such sequence.

a_{1} = \frac{\sqrt{2}}{4} (\sqrt{2} - 1); a_{n + 1} = a_{n} (\sqrt{2} - 1), n \in N

a_{1} = \frac{\sqrt{2}}{4}; a_{n + 1} = a_{n} (\sqrt{2} - 1), n \in N

a_{1} = \sqrt{2} - 1; a_{n + 1} = a_{n} (\sqrt{2} - 1), n \in N

a_{1} = \frac{\sqrt{2}}{4} (\sqrt{2} - 1); a_{n + 1} = a_{n} {(\sqrt{2} - 1)}^{2}, n \in N