2010013021

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2010013021
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O aký vektor \(\vec{u}\) musí byt posunutý graf funkcie \(f(x)=5^{3-x}-4\), aby vznikol graf funkcie \(f(x) =\left(\frac15\right)^{x+1}-6\)?
\(\vec{u}=\left(-4;-2\right)\)
\(\vec{u}=\left(4;2\right)\)
\(\vec{u}=\left(4;-2\right)\)
\(\vec{u}=\left(-4;2\right)\)