Level:
Project ID:
9000141905
Source Problem:
Accepted:
1
Clonable:
1
Easy:
1
Given the function \(g\) (see the picture),
find \(\lim _{x\to 1}g(x)\).
\[
g(x)=\begin{cases}
-\frac12(x-1)^2+2 & \text{if } x < 1,\\
\frac2{x^2}+1 & \text{if } x \geq 1
\end{cases}
\]
This limit does not exist.
\(3\)
\(2\)
\(1\)
Fixed Answer:
First Fixed