Level:
Project ID:
9000128804
Accepted:
1
Clonable:
0
Easy:
0
The base \(ABCD\) of a square
pyramid \(ABCDV \) has side
\(6\, \mathrm{cm}\). The height of the
pyramid is \(4\, \mathrm{cm}\). Find the
distance between the line \(AD\)
and the plane \(BCV \).
\(\frac{24}
{5} \, \mathrm{cm}\)
\(\frac{15\sqrt{34}}
{5} \, \mathrm{cm}\)
\(6\, \mathrm{cm}\)