9000021806

Level: 
Project ID: 
9000021806
Source Problem: 
Accepted: 
1
Clonable: 
1
Easy: 
0
Solve the following inequality. \[ \frac{1 - 3x} {x + 2} \geq 0 \]
\(x\in \left (-2; \frac{1} {3}\right ] \)
\(x\in \left [ \frac{1} {3};\infty \right )\)
\(x\in \left (\frac{1} {3};\infty \right )\)
\(x\in (-\infty ;-2)\cup \left [ \frac{1} {3};\infty \right )\)