Level:
Project ID:
1003107805
Accepted:
1
Define the function $f(x)$ so that it holds: $f'(x)=x^5-\sqrt[4]x$ on $(0;\infty)$, $f(1)=-1$.
$f(x)=\frac{x^6}6-\frac45x\sqrt[4]x-\frac{11}{30}$
$f(x)=\frac{x^6}6-\frac45\sqrt[4]{x^5}+\frac{11}{30}$
$f(x)=\frac{x^6}6-\frac54x\sqrt[4]x-\frac{11}{30}$
$f(x)=\frac{x^6}6-\frac54x\sqrt[4]x+\frac{11}{30}$