Volume and surface of solids

1103164601

Level: 
B
Let there be a triangular prism with the base area of \( 8\,\mathrm{cm}^2 \) and the height of \( 10\,\mathrm{cm} \) (see the picture). The volume of the prism is:
\( 80\,\mathrm{cm}^3 \)
\( 40\,\mathrm{cm}^3 \)
\( \frac{80}3\,\mathrm{cm}^3 \)
\( 20\,\mathrm{cm}^3 \)

1003170706

Level: 
B
A snack bar sells popcorn in cone-shaped containers. One such container has the diameter of \( 20.32\,\mathrm{cm} \) and the height of \( 25.4\,\mathrm{cm} \). Find the volume of this container and leave your answer in litres.
\( 2.75\,\mathrm{l} \)
\( 8.24\,\mathrm{l} \)
\( 10.98\,\mathrm{l} \)
\( 0.54\,\mathrm{l} \)

1103170705

Level: 
B
A cone has the lateral area of \( 72\,\mathrm{dm}^2 \) and the slant height of \( 80\,\mathrm{cm} \). Find the volume of this cone. Round your answer to \( 2 \) decimal places.
\( 64.20\,\mathrm{dm}^3 \)
\( 192.59\,\mathrm{dm}^3 \)
\( 69.74\,\mathrm{dm}^3 \)
\( 23.25\,\mathrm{dm}^3 \)

1103170702

Level: 
B
Let there be a cone with the base diameter of \( 8\,\mathrm{cm} \) and the slant height of \( 5\,\mathrm{cm} \). Find the volume and surface area of the cone. Leave your answer in terms of \( \pi \).
\( V=16\pi\,\mathrm{cm}^3 \), \( S=36\pi\,\mathrm{cm}^2 \)
\( V=64\pi\,\mathrm{cm}^3 \), \( S=104\pi\,\mathrm{cm}^2 \)
\( V=64\pi\,\mathrm{cm}^3 \), \( S=104\pi\,\mathrm{cm}^2 \)
\( V=16\pi\,\mathrm{cm}^3 \), \( S=28\pi\,\mathrm{cm}^2 \)

1103170701

Level: 
B
Let there be a cone with the base radius of \( 6\,\mathrm{cm} \) and the perpendicular height of \( 8\,\mathrm{cm} \). Find the volume and surface area of the cone. Leave your answer in terms of \( \pi \).
\( V=96\pi\,\mathrm{cm}^3 \), \( S=96\pi\,\mathrm{cm}^2 \)
\( V=96\pi\,\mathrm{cm}^3 \), \( S=84\pi\,\mathrm{cm}^2 \)
\( V=288\pi\,\mathrm{cm}^3 \), \( S=84\pi\,\mathrm{cm}^2 \)
\( V=16\pi\,\mathrm{cm}^3 \), \( S=96\pi\,\mathrm{cm}^2 \)

1103165906

Level: 
B
The volume of a cylinder with the height of \( 12\,\mathrm{cm} \) is \( 60\,\mathrm{cm}^3 \). Find the surface area of this cylinder. Round your result to \( 2 \) decimal places.
\( 105.12\,\mathrm{cm}^2 \)
\( 52.56\,\mathrm{cm}^2 \)
\( 135.54\,\mathrm{cm}^2 \)
\( 210.24\,\mathrm{cm}^2 \)