2010011903 Level: CFind the solution set of the given inequality. \[ \frac{x+1}{|3-x|} < 1 \]\( (-\infty;1) \)\( [ -1;3)\)\([ 1,3)\cup(3;\infty) \)\((-\infty;-1 ]\)
2010011902 Level: CFind the solution set of the given inequality. \[ \frac{|3x+4|}{2-x} > 1 \]\( (-\infty;-3)\cup\left(-\frac12;2\right) \)\( (2;\infty)\)\( (-\infty;-3)\cup(2;\infty) \)\((-3;-\frac12 ]\)
2010011901 Level: CFind the solution set of the given inequality. \[ \frac{|4x+1|}{x(x+3)} \leq 0 \]\( (-3;0) \)\( [ -3;0 ] \)\( (-\infty;-3)\cup(0;\infty) \)\(\left(-3;-\frac14 \right]\)
2000005308 Level: CUse the graphs of the functions \(f(x)=x-3\) and \(g(x)=4-x\) to find the solution set of the following inequality. \[\frac{x-3}{4-x} < 0\]\( x \in (-\infty;3) \cup (4;+\infty) \)\( x \in (3;4) \)\( x \in (-\infty;3) \)\( x \in (-\infty;0) \)
2000005307 Level: CUse the graphs of the functions \(f(x)=x+3\) and \(g(x)=x-1\) to find the solution set of the following inequality. \[\frac{x+3}{x-1} \leq 0\]\( x \in [ -3;1) \)\( x \in [ -3;1] \)\( x \in (1;+\infty) \)\( x \in (-1;+\infty) \)
2000005306 Level: CUse the graphs of the functions \(f(x)=x^2-4\) and \(g(x)=x+2\) to find the solution set of the following inequality. \[\frac{x^2-4}{x+2} \geq 0\]\( x \in [ 2;+\infty) \)\( x \in ( 2;+\infty) \)\( x \in (-\infty;-2) \cup ( 2;+\infty) \)\( x \in (-\infty;-2] \cup [ 2;+\infty) \)
2000005305 Level: BFind all real values of \(x\) such that the fraction \( \frac{7}{x^2+1} \) is negative.\( \emptyset \)\( x \in \mathbb{R} \)\( x \in (-1;+\infty) \)\( x \in \mathbb{R}\setminus \{ \pm 1\}\)
2000005304 Level: BFind all real values of \( x\) such that the fraction \( \frac{5}{x^2}\) is positive.\( x \in \mathbb{R}\setminus \{0\}\)\( x \in \mathbb{R}\)\( x \in (0;+\infty)\)\( x \in [ 0;+\infty)\)
2000005303 Level: CUse the graphs of the functions \( f(x)=x^2-5x+4\) and \(g(x)=x^2+2x-3\) to find the solution set of the following equation. \[ \frac{x^2-5x+4}{x^2+2x-3}=1\]\( \emptyset\)\( \{1\}\)\( \{-3;4\}\)\( \{-3;1;4\}\)
2000005302 Level: CUse the graphs of the functions \(f(x)=x^2-x-6\) and \(g(x)=x-3\) to find the solution set of the following equation. \[\frac{x^2-x-6}{x-3}=1\]\( \{ -1\} \)\( \{ 3\} \)\( \{ -1;3\} \)\( \{ -2;3\} \)