Graf funkcie a hodnoty jej derivácie

Project ID: 
6000000054
Accepted: 
Podoblasť: 
Typ: 
Layout: 
Question: 
Grafu funkcie $f$ priraďte správne tvrdenie týkajúce sa derivácie $f'$ funkcie $f$.
Questions Title: 
Grafy:
Answers Title: 
Tvrdenie:
Question 1: 
{\obrA}
Question 1 Image: 
Answer 1: 

$f'(-2)=1$, $f'(0)$ neexistuje, $f'(2)=-2$

Question 2: 
{\obrB}
Question 2 Image: 
Answer 2: 

$f'(-2)=1$, $f'(0)=0$, $f'(2)=-2$

Question 3: 
{\obrC}
Question 3 Image: 
Answer 3: 

$f'(-2)=0$, $f'(0)$ neexistuje, $f'(2)=-2$

Question 4: 
{\obrD}
Question 4 Image: 
Answer 4: 

$f'(-2)=-1$, $f'(0)=2$, $f'(2)=0$

Answer 5: 

$f'(-2)=0$, $f'(0)$ neexistuje, $f'(2)=-1$

Answer 6: 

$f'(-2)=1$, $f'(0)=2$, $f'(2)=-2$

Tex: 
% tiket 32300 \NastavOD{2} \def\obrA{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,-2) -- (0,2) -- (1,2) -- (4,-4); \draw[red] (1,2) node [above right]{$f$}; }} \def\obrB{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,-2) -- (-1,1) -- (1,1) -- (3,-3); \draw[red] (1,1) node [above right]{$f$}; }} \def\obrC{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,1) -- (0,1) -- (1,2) -- (4,-4); \draw[red] (1,2) node [above right]{$f$}; }} \def\obrD{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,2) -- (-1,-1) -- (1,3) -- (4,3); \draw[red] (1,3) node [above left]{$f$}; }}