Graph of Function and Values of its Derivative

Project ID: 
6000000054
Accepted: 
SubArea: 
Type: 
Layout: 
Question: 
Match a graph of f with the correct statement about the derivative f of the function f.
Questions Title: 
Graphs:
Answers Title: 
Statements:
Question 1: 
{\obrA}
Question 1 Image: 
Answer 1: 

f(2)=1, f(0) does not exist, f(2)=2

Question 2: 
{\obrB}
Question 2 Image: 
Answer 2: 

f(2)=1, f(0)=0, f(2)=2

Question 3: 
{\obrC}
Question 3 Image: 
Answer 3: 

f(2)=0, f(0) does not exist, f(2)=2

Question 4: 
{\obrD}
Question 4 Image: 
Answer 4: 

f(2)=1, f(0)=2, f(2)=0

Answer 5: 

<p>$f'(-2)=0$, $f'(0)$ does not exist, $f'(2)=-1$</p>

Answer 6: 

f(2)=1, f(0)=2, f(2)=2

Tex: 
% tiket 32300 \NastavOD{2} \def\obrA{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,-2) -- (0,2) -- (1,2) -- (4,-4); \draw[red] (1,2) node [above right]{$f$}; }} \def\obrB{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,-2) -- (-1,1) -- (1,1) -- (3,-3); \draw[red] (1,1) node [above right]{$f$}; }} \def\obrC{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,1) -- (0,1) -- (1,2) -- (4,-4); \draw[red] (1,2) node [above right]{$f$}; }} \def\obrD{\obrMsr[x=0.6cm,y=0.6cm]{-4}{4}{-3}4 { \footnotesize \obrClip \draw[gray!30, thin, step=1] (-4,-3) grid (4,4); \obrOsaX[above left] \obrOsaY[below right] \obrPopisX[below]{-2,2} \obrPopisY[left]{-2,2} \obrZnackyX{-3,-1,1,3} \obrZnackyY{-1,1,3} \draw[thick,red] (-4,2) -- (-1,-1) -- (1,3) -- (4,3); \draw[red] (1,3) node [above left]{$f$}; }}