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Project ID:
2010013019
Source Problem:
Accepted:
0
Clonable:
1
Easy:
0
O aký vektor \(\vec{u}\) musí byt posunutý graf funkcie \(f(x)=\left(\frac14\right)^{5-x}-1\), aby vznikol graf funkcie \(f(x)=4^{x-2}+3\)?
\(\vec{u}=\left(-3;4\right)\)
\(\vec{u}=\left(-3;-4\right)\)
\(\vec{u}=\left(3;4\right)\)
\(\vec{u}=\left(3;-4\right)\)