2010006306

SubArea: 
Conics
Level: 
B
Project ID: 
2010006306
Source Problem: 
1003024101
Accepted: 
0
Clonable: 
1
Easy: 
0
The equation of a hyperbola with the center S=[1;−3], the focus F=[1;2], and the vertex A=[1;0] is given by:
(y+3)29−(x−1)216=1
(x−1)216−(y+3)29=1
(x−1)29−(y+3)216=1
(y+3)216−(x−1)29=1
(x+1)216−(y−3)29=1