Triangles

1103021808

Level: 
B
There is a cottage on the top of the mountain. From our site \( P \), \( 2\,\mathrm{km} \) as the crow flies from the cottage, we can observe the cottage to be at an angle of elevation of \( 30^{\circ} \). How many altitude meters do we still have to overcome to get to the cottage?
\( 1000\,\mathrm{m} \)
\( 1732\,\mathrm{m} \)
\( 2\,\mathrm{km} \)
\( 1155\,\mathrm{m} \)

1103256902

Level: 
B
The cucumber field has the shape of an isosceles right triangle. The length of its legs is \( 12\,\mathrm{m} \). Rotary sprinklers placed in its vertices have a reach of \( 6\,\mathrm{m} \). Find the area of the field that is not sprinkled with water. Round the result to two decimal places.
\( 15.45\,\mathrm{m}^2 \)
\( 41.10\,\mathrm{m}^2 \)
\( 16.29\,\mathrm{m}^2 \)
\( 15.25\,\mathrm{m}^2 \)

2000005601

Level: 
B
A right-angled triangle \(ABC\) with the right angle at the vertex \(C\) is given in the picture. The length of the side \(c\) is \(5\,\mathrm{cm}\) and the measure of the angle \(\alpha\) is \(35^{\circ}\). What is the length of the side \(a\)?
\(5\sin{35^{\circ}}\,\mathrm{cm}\)
\(\frac{5}{\sin{35^{\circ}}}\,\mathrm{cm}\)
\(5\cos{35^{\circ}}\,\mathrm{cm}\)
\(\frac{5}{\cos{35^{\circ}}}\,\mathrm{cm}\)

2000005602

Level: 
B
A right-angled triangle \(ABC\) is given in the picture. Its hypotenuse is \(10\,\mathrm{cm}\) long and the measure of its internal angle \(\alpha\) is \(30^{\circ}\). What are the lengths of the legs in the triangle?
\( a=5\,\mathrm{cm}\), \( b=5\sqrt{3}\,\mathrm{cm}\)
\( a=5\sqrt{3}\,\mathrm{cm}\), \( b=5\,\mathrm{cm}\)
\(a=10\cos{30^{\circ}}\,\mathrm{cm}\), \(b=10\sin{35^{\circ}}\,\mathrm{cm}\)
\(a=\frac{\sin{30^{\circ}}}{10}\,\mathrm{cm}\), \(b=\frac{\cos{30^{\circ}}}{10}\,\mathrm{cm}\)

2000005603

Level: 
B
A right-angled triangle \(ABC\) with the right angle at the vertex \(C\) is given in the picture. Calculate the length of the side \(b\), if \(a=20\,\mathrm{cm}\) and \(\beta=34^{\circ}\).
\(b=\frac{20}{ \mathop{\mathrm{tg}} {56^{\circ}}}\,\mathrm{cm}\)
\(b=\frac{20}{ \mathop{\mathrm{tg}} {34^{\circ}}}\,\mathrm{cm}\)
\( b=20\sin{34^{\circ}}\,\mathrm{cm}\)
\( b=20\cos{34^{\circ}}\,\mathrm{cm}\)

2000005604

Level: 
B
A right-angled triangle \(ABC\) with the right angle at the vertex \(C\) is given in the picture. Calculate the height \(v_c\), if \(a=20\,\mathrm{cm}\) and \(\beta=50^{\circ}\).
\( 20\sin{50^{\circ}}\)
\( 20\cos{50^{\circ}}\)
\( 20 \mathop{\mathrm{tg}} {50^{\circ}}\)
\( \frac{20}{\sin{50^{\circ}}}\)