9000003106 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = \frac{2} {x+1}\)\(y = \frac{1} {x+2}\)\(y = - \frac{1} {x+2}\)\(y = \frac{1} {x-1}\)
9000003109 Level: BIdentify the function that is graphed in the picture.\(f(x) = \frac{x+3} {x+2}\)\(f(x) = \frac{x+2} {x+1}\)\(f(x) = \frac{x-2} {x+1}\)\(f(x) = -\frac{x+3} {x+2}\)
9000003107 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = -2 + \frac{1} {x+1}\)\(y = 2 + \frac{1} {x+1}\)\(y = 2 + \frac{1} {x-1}\)\(y = -2 + \frac{1} {x-1}\)
9000003110 Level: BIdentify the function that is graphed in the picture.\(f(x) = \frac{2-x} {1-x}\)\(f(x) = \frac{x-2} {x+1}\)\(f(x) = -\frac{2-x} {1-x}\)\(f(x) = \frac{x-1} {x+1}\)
9000003108 Level: BIdentify a possible analytic expression for the function graphed in the picture.\(y = -2 - \frac{1} {x-1}\)\(y = -1 - \frac{1} {x-2}\)\(y = -2 + \frac{1} {x-1}\)\(y = 1 - \frac{1} {x-2}\)
9000002903 Level: BIn the following list identify a point which is on the graph of the function \(f(x) = \frac{3} {x} - 5\).\(A = \left [-6,-\frac{11} {2} \right ]\)\(A = \left [-1,-2\right ]\)\(A = \left [-3,-\frac{5} {2}\right ]\)\(A = \left [\frac{1} {2},-1\right ]\)
9000003604 Level: BSolve the following equation. \[ 10^{x} - 5^{x-1}\cdot 2^{x-2} = 950 \]\(x = 3\)\(x = 1\)\(x = 2\)\(x = 4\)
9000002904 Level: BLet by \(X\) and \(Y\) denote the intersection points of the graph of the function \(f(x) = - \frac{1} {x-1} + 1 \) with \(x\) and \(y\)-axis, respectively. Find coordinates of \(X\) and \(Y\).\(X = [2,0]\), \(Y = [0,2]\)\(X = [1,0]\), \(Y = [0,1]\)\(X = [0,2]\), \(Y = [2,0]\)\(X = Y = [0,0]\)
9000003608 Level: BSolve the following equation. \[ \frac{2} {3}\cdot 9^{x+1} - 13\cdot 6^{x} + 24\cdot 4^{x-1} = 0 \]\(1,\ -1\)\(\frac{3} {2},\ \frac{2} {3}\)\(\frac{1} {2},\ -\frac{1} {2}\)\(\frac{3} {2},\ -\frac{3} {2}\)
9000002905 Level: BFind the range of the function \(f(x)= \frac{1} {x-2} + 1\).\((-\infty ,1)\cup (1,\infty )\)\(\mathbb{R}\)\((-\infty ,2)\cup (2,\infty )\)\((-\infty ,-1)\cup (-1,\infty )\)