Derivácia funkcie

9000063307

Časť: 
C
Derivácia funkcie \(f\colon y =\ln \left(\cos 2x\right)\) je rovná:
\(f'(x) = -2\mathop{\mathrm{tg}}\nolimits 2x,\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (-\frac{\pi }{4} + k\pi ; \frac{\pi } {4} + k\pi \right )\)
\(f'(x) = 2\mathop{\mathrm{tg}}\nolimits 2x,\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (-\frac{\pi }{4} + k\pi ; \frac{\pi } {4} + k\pi \right )\)
\(f'(x) = -2,\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (-\frac{\pi }{4} + k\pi ; \frac{\pi } {4} + k\pi \right )\)
\(f'(x) = 1 -\ln\left(\sin 2x\right),\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (k\pi ; \frac{\pi } {2} + k\pi \right )\)

9000063101

Časť: 
B
Derivácia funkcie \(f\colon y = \frac{x^{2}-1} {x^{2}+1}\) je rovná:
\(f'(x) = \frac{4x} {(x^{2}+1)^{2}} ,\ x\in \mathbb{R}\)
\(f'(x) = \frac{-4x} {x^{2}+1},\ x\in \mathbb{R}\)
\(f'(x) = \frac{4x^{3}} {(x^{2}+1)^{2}} ,\ x\in \mathbb{R}\)
\(f'(x) = \frac{4x} {x^{2}+1},\ x\in \mathbb{R}\)

9000063103

Časť: 
B
Derivácia funkcie \(f\colon y = \frac{x^{2}-x} {x+1} \) je rovná:
\(f'(x) = \frac{x^{2}+2x-1} {(x+1)^{2}} ,\ x\neq - 1\)
\(f'(x) = 2x - 1,\ x\neq - 1\)
\(f'(x) = \frac{x^{2}+2x-1} {(x+1)^{2}} ,\ x\neq 0\)
\(f'(x) = \frac{2x} {(x^{2}+1)^{2}} ,\ x\neq 0\)

9000063104

Časť: 
B
Derivácia funkcie \(f\colon y = \frac{\sin x} {\sin x-\cos x}\) je rovná:
\(f'(x) = \frac{-1} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\sin ^{2}x-\cos ^{2}x} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\sin x(\cos x+1)} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\cos ^{2}x-\sin ^{2}x} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)