9000063606
Level:
A
Find the following limit.
\[
\lim _{n\to \infty }\frac{3n^{2} - 2n + 1}
{2n^{3} - 4}
\]
\(0\)
\(\frac{3}
{2}\)
\(\frac{1}
{2}\)
\(-\frac{1}
{4}\)
Limit of a sequence
9000063609
Level:
A
Find the following limit.
\[
\lim _{n\to \infty }\left ( \frac{n}
{n - 1} + \frac{n + 2}
{n + 1}\right )
\]
\(2\)
\(- 1\)
\(0\)
\(1\)
1003035902
Level:
B
Find the limit \( \lim\limits_{n\rightarrow\infty}(-1)^n\cdot\frac{3n}{4n^2+7} \).
\( 0 \)
\( \frac34 \)
\( -\frac34 \)
\( \frac37 \)
\( -\infty \)
1003035907
Level:
B
Find the limit of the sequence \( \left(\left( \frac32 \right)^n \right)_{n=1}^{\infty} \).
\( \lim\limits_{n\rightarrow\infty}\left( \frac32 \right)^n =\infty \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac32 \right)^n =\frac32 \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac32 \right)^n =\frac{81}{16} \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac32 \right)^n = 0\)
\( \lim\limits_{n\rightarrow\infty}\left( \frac32 \right)^n \) does not exist.
1003035908
Level:
B
Find the limit of the sequence \( \left(\left( \frac23 \right)^n\right)_{n=1}^{\infty} \).
\( \lim\limits_{n\rightarrow\infty}\left( \frac23 \right)^n =0 \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac23 \right)^n =-\infty \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac23 \right)^n =\frac{16}{81} \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac23 \right)^n =\frac23 \)
\( \lim\limits_{n\rightarrow\infty}\left( \frac23 \right)^n \) does not exist.
1003035909
Level:
B
Find the limit of the sequence \( \left(\left( -\frac32 \right)^n \right)_{n=1}^{\infty} \).
\( \lim\limits_{n\rightarrow\infty}\left( -\frac32 \right)^n \) does not exist.
\( \lim\limits_{n\rightarrow\infty}\left( -\frac32 \right)^n = \infty \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac32 \right)^n = 0 \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac32 \right)^n = -\infty \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac32 \right)^n = -\frac32\)
1003035910
Level:
B
Find the limit of the sequence \( \left( \left( -\frac23 \right)^n \right)_{n=1}^{\infty} \).
\( \lim\limits_{n\rightarrow\infty}\left( -\frac23 \right)^n=0 \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac23 \right)^n=-\infty \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac23 \right)^n=-\frac23 \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac23 \right)^n=-\frac32 \)
\( \lim\limits_{n\rightarrow\infty}\left( -\frac23 \right)^n \) does not exist.
1003047401
Level:
B
Choose the correct formula to calculate the limit. \[ L=\lim\limits_{n\rightarrow\infty}\frac{3\cdot5^n+2\cdot6^n}{2\cdot5^n+4\cdot7^n } \]
\( L=\lim\limits_{n\rightarrow\infty} \frac{3\cdot\left(\frac57\right)^n+2\cdot\left(\frac67\right)^n}{2\cdot\left(\frac57\right)^n+4} =0 \)
\( L=\lim\limits_{n\rightarrow\infty}\frac{3\cdot\left(\frac56\right)^n+2}{2\cdot\left(\frac57\right)^n+4}=\frac12 \)
\( L=\lim\limits_{n\rightarrow\infty}\frac{3+2\cdot\left(\frac65\right)^n}{2+4\cdot\left(\frac75\right)^n } =\frac32 \)
\( L=\frac{3\cdot5^{\infty}+2\cdot6^{\infty}}{2\cdot5^{\infty}+4\cdot7^{\infty}}=\infty \)
\( L=\lim\limits_{n\rightarrow\infty}\frac{3\cdot\left(\frac57\right)^n+2\cdot\left(\frac67\right)^n}{2\cdot\left(\frac57\right)^n+4\cdot\left(\frac77\right)^n}=\frac56 \)
1003047402
Level:
B
Choose the best first step to simplify and calculate the limit of the following sequence. \[ \left(\frac{3\cdot5^n+2\cdot6^n}{2\cdot5^n+4\cdot6^n}\right)_{n=1}^{\infty} \]
We take \( 6^n \) outside the brackets in the numerator and the denominator.
We take \( 5^n \) outside the brackets in the numerator and denominator.
We divide the numerator and denominator by \( 5^n \).
We divide the numerator by \( 6^n \).
We divide the denominator by \( 6^n \).
1003047403
Level:
B
Find the limit \( \lim\limits_{n\rightarrow\infty}\frac{5^{n+1}+6^{n+1}}{5^{n+1}+6^n} \).
\( 6 \)
\( 5 \)
\( \frac56 \)
\( 0 \)
\( \infty \)