Combinatorics

9000136905

Level: 
B
For \(n\in \mathbb{N}\), \(n\geq 2\), the difference \(\left({n\above 0.0pt 2} \right) -\left ({ n\above 0.0pt n-2}\right)\) equals to:
\(0\)
\(\left (n + 2\right )\left (n + 1\right )\)
\(\left({n+2\above 0.0pt n} \right)\)
\(n^{2} - 1\)
\(\left({n\above 0.0pt n}\right)\)