A stone has been thrown vertically up at the velocity
\(15\, \mathrm{m}\, \mathrm{s}^{-1}\) from the
initial height \(10\, \mathrm{m}\).
How long (in seconds) has been the height of the stone at least
\(20\, \mathrm{m}\)?
Hint: The height \(h\) is
given by the expression \(h = s_{0} + v_{0}t -\frac{1}
{2}gt^{2}\), the
standard acceleration is \(g\mathop{\mathop{\doteq }}\nolimits 10\, \mathrm{m}\, \mathrm{s}^{-2}\).