Antiderivative - Trigonometric Functions

Project ID: 
7500020172
Question: 
Create matching triples, each containing a function $f$, an algebraically modified form of $f$, and an antiderivative $F$ of $f$.
Header 1: 
Function $f$
Header 2: 
Function $f$ after algebraic modification
Header 3: 
Antiderivative $F$
Text 11: 
$$ f(x)=\frac{1}{\sin^2 x \cos^2 x} $$
Text 21: 
$$ f(x)=\frac{\sin^2 x +\cos^2 x}{\sin^2 x \cos^2 x} $$
Text 31: 
$$ F(x) = \mathrm{tg}\,x - \mathrm{cotg}\,x $$
Text 12: 
$$ f(x)=\frac{\cos 2x}{\sin x +\cos x} $$
Text 22: 
$$ f(x)=\frac{\cos^2 x - \sin^2 x}{\sin x + \cos x} $$
Text 32: 
$$ F(x) = \sin x + \cos x $$
Text 13: 
$$ f(x)=\frac{\cos 2x}{\sin^2 x \cos^2 x} $$
Text 23: 
$$ f(x)=\frac{\cos^2 x - \sin^2 x}{\sin^2 x \cos^2 x} $$
Text 33: 
$$ F(x) = - \mathrm{cotg}\,x - \mathrm{tg}\,x $$
Text 14: 
$$ f(x)=\frac{1+\cos 2x}{2\sin^2 x \cos^2 x} $$
Text 24: 
$$ f(x)=\frac{1+\cos^2 x-\sin^2 x}{2\sin^2 x \cos^2 x} $$
Text 34: 
$$ F(x) = - \mathrm{cotg}\,x $$
Text 15: 
$$ f(x)=\frac{1+ \sin 2x}{\sin x + \cos x} $$
Text 25: 
$$ f(x)=\frac{\sin^2 x+ \cos^2 x+ 2\sin x \cos x}{\sin x + \cos x} $$
Text 35: 
$$ F(x) = - \cos x + \sin x $$
Text 16: 
$$ f(x)=\frac{2 \mathrm{tg}\,x}{\sin 2x } $$
Text 26: 
$$ \frac{2\frac{\sin x}{\cos x}}{2\sin x \cos x} $$
Text 36: 
$$ F(x) = \mathrm{tg}\,x $$
Workflow: 
translation