Podoblasť: Geometria v rovineČasť: BProject ID: 9000107508Accepted: 1Clonable: 0Easy: 0Kosínus odchýlky priamok \(p\colon x = t;\ y = -3;\ t\in \mathbb{R}\) a \(q\colon y = 1\) je rovný:\(1\)\(\frac{1} {\sqrt{2}}\)\(0\)\(\frac{\sqrt{10}} {10} \)