9000139702

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Project ID: 
9000139702
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1
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Easy: 
1
A race was attended by \(12\) competitors. Find the number of possible orderings of the competitors on the first three places of the scoreboard.
\(\frac{12!} {9!} =1\:320\)
\(3^{12}=531\:441\)
\(\frac{12!} {9!\, 3!}=220\)
\(12!\, 3!=2\:874\:009\:600\)