Altitude of Triangle II

Project ID: 
7200000094
Accepted: 
SubArea: 
Type: 
Layout: 
Question: 
Point $D$ (the foot of the altitude $CD$) divides side $c$ of triangle $ABC$ into two segments of lengths $c_a$ and $c_b$, such that $c=c_a+c_b$ (see the picture). Match each triangle, specified by the lengths of the segments or the side $c$ and the size of an inner angle, to the length of its altitude $CD$ rounded to two decimal places.
Unfolding Image: 
Questions Title: 
Triangle
Answers Title: 
Lenght of Altitude $CD$
Question 1: 
\begin{aligned} c_a&=3\cr c_b&=5\cr \beta&=35^\circ \end{aligned}
Answer 1: 
$$3.5$$
Question 2: 
\begin{aligned} c_a&=2.5\cr c_b&=6.1\cr \beta&=40^\circ \end{aligned}
Answer 2: 
$$5.12$$
Question 3: 
\begin{aligned} c&=10.3\cr c_b&=6.2\cr \alpha&=60^\circ \end{aligned}
Answer 3: 
$$7.10$$
Question 4: 
\begin{aligned} c_a&=5.4\cr c_b&=3.7\cr \alpha&=45^\circ \end{aligned}
Answer 4: 
$$5.4$$
Question 5: 
\begin{aligned} c&=11.5\cr c_b&=4.2\cr \beta&=60^\circ \end{aligned}
Answer 5: 
$$12.64$$
Question 6: 
\begin{aligned} c&=11.8\cr c_b&=3.5\cr \alpha&=30^\circ \end{aligned}
Answer 6: 
$$4.79$$
Answer 7: 
$$10.74$$
Answer 8: 
$$2.1$$