SubArea: ConicsLevel: CProject ID: 2010006004Source Problem: 1003024111Accepted: 0Clonable: 1Easy: 0The equation of a parabola is given by x2−8x+3y−2=0. Find the equation of a line, which passes through the vertex of this parabola and is parallel to the line 2x−5y+8=0.−2x+5y−22=02x−5y−22=02x−5y−38=02x−5y+38=0−2x+5y+22=0