SubArea: ConicsLevel: CProject ID: 1003024111Source Problem: 2010006004Accepted: 1Clonable: 1Easy: 0The equation of a parabola is given by y2−12x−6y+57=0. Find the equation of a line, which passes through the vertex of this parabola and is parallel to the line 5x−3y−2=0.5x−3y−11=0−5x+3y−11=05x−3y−3=05x−3y+11=0−5x+3y−3=0