Level:
Project ID:
1003040207
Accepted:
1
Clonable:
0
Easy:
0
Given the points $A = [2;0;3]$ and $B = [-1;2;0]$, specify all the points $C$ lying on the $z$-axis, such that the area of the triangle $ABC$ is $2\sqrt2$.
Hint: Use a cross product of vectors.
$C_1=[0;0;1];\ C_2=\left[0;0;\frac{29}{13}\right]$
$C_1=[0;0;1];\ C_2=\left[0;0;-1\right]$
$C_1=[0;0;-1];\ C_2=\left[0;0;\frac{13}{29}\right]$
$C_1=[0;0;-1];\ C_2=\left[0;0;\frac{29}{13}\right]$