Level:
Project ID:
1003024607
Accepted:
1
Clonable:
0
Easy:
0
On the shelf, there should be three blue cups, three red cups, two yellow cups and two green cups arranged in a row from the left to the right. The cups of the same color are not mutually distinguishable. How many arrangements of these cups are possible?
\( \frac{10!}{(2!)^2\cdot(3!)^2}=25\:200 \)
\( \frac{10!}{4\cdot6!}=1\:260 \)
\( \frac{10!}{2\cdot2!\cdot3!}=151\:200 \)
\( \frac{10!}{4\cdot2!\cdot3!}=75\:600 \)