1003024602

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1003024602
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Suppose six pupils are sitting on six chairs in a row. Among them there are twins. In how many ways can the pupils be seated in the row so that the twins do not sit next to each other?
\( 6! -2\cdot5!=480 \)
\( \frac{6!}2=360 \)
\( 2\cdot5!=240 \)
\( 6! -5!=600 \)