Roots of Rational Equations

Wysłane przez michaela.bailova w śr., 04/17/2024 - 21:59

Project ID:

7100020075

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Question:

Niech

x \in R

. Każda para, której szukasz, jest równaniem i liczbą jego rozwiązań. Każde rozwiązanie policz tyle razy, ile jest jego krotności.

Question 1:

\frac{(x - 1) (x - 2) (x + 2)^{2}}{x^{2} - 4} = 0

Answer 1:

1

Question 2:

\frac{(x - 4) (x - 2) (2 x^{2} + 8)^{2}}{x^{2} + 4} = 0

Answer 2:

2

Question 3:

\frac{2 x (x + 3) (x - 3)}{x^{3} - 9 x} = 0

Answer 3:

0

Question 4:

\frac{2 x (x - 4)^{2} (x^{3} + 8) (x^{3} - 8)}{x^{4} - 16} = 0

Answer 4:

3

Question 5:

\frac{2 x (x^{2} - 16) (x + 3)}{x^{2} - 1} = 0

Answer 5:

$4$

Question 6:

\frac{2 (x + 1) (x^{3} - 16 x) (x - 3)}{x^{2} + 1} = 0

Answer 6:

5

Question 7:

\frac{2 (x - 1)^{4} (x^{3} + 1)^{2}}{x^{3}} = 0

Answer 7:

6

Question 8:

\frac{(x^{4} - 1) (2 x^{3} - 18 x) (x^{2} - 6)}{(x^{2} + 1) (x^{2} + 6) (x - 9)} = 0

Answer 8:

7

Question 9:

\frac{(x^{2} - 3) (x^{2} - 4)^{3}}{x^{3} + 4} = 0

Answer 9:

8

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