$\mathrm{cot}\frac{\pi}{64}$

Project ID: 
3000000094
Question: 

Using a calculator, determine $\cot\frac{\pi}{64}$. Round the result to four decimal places.

Adele followed these steps:

(1) She converted the angle from radians to degrees: $$\cot\frac{\pi}{64}=\cot\left(\frac{45}{16}\right)^\circ$$

(2) She stated that for any angle $x$ where the functions $\tan(x)$ and $\cot(x)$ exist, these functions are reciprocals of each other.

(3) Based on statement (2), she concluded that: $$\cot\left(\frac{45}{16}\right)^\circ=\tan\left(\frac{16}{45}\right)^\circ$$

(4) Therefore, using a calculator, she calculated: $$\tan\left(\frac{16}{45}\right)^\circ\approx 0.0062$$ (rounded to four decimal places) and declared this as the final result.

However, her result is incorrect. In which step did Adele make a mistake?

Answer 1: 

The mistake is in step (1). The conversion of the angle to degrees was unnecessary, but since she chose to convert it, it should have been done correctly.

Answer 2: 

The mistake is in step (2). The claim that $\tan(x)$ and $\cot(x)$ are always reciprocal functions is not true.

Answer 3: 

The mistake is in step (3). The equation $\cot\left(\frac{45}{16}\right)^\circ=\tan\left(\frac{16}{45}\right)^\circ$ is not true.

Answer 4: 

The mistake is in step (4). Adele made a mistake when using the calculator. She likely had the calculator set to radians instead of degrees when entering the angle in degrees.

Fixed Answer: 
All Fixed
Correct Answer: 
Answer 3
Hint: 

For every angle $x$ for which the functions $\tan(x)$ and $\cot(x)$ are defined, these functions are reciprocals of each other, meaning: $$\cot x=\frac{1}{\tan x}$$ Therefore $$\cot\frac{\pi}{64}=\frac{1}{\tan\frac{\pi}{64}}\approx20.3555,$$ or using the degree conversion correctly: $$\cot\frac{\pi}{64}=\cot\left(\frac{45}{16}\right)^\circ=\frac{1}{\tan\left(\frac{45}{16}\right)^\circ }\approx20.3555.$$