2010007904 Level: BFind out, how many integer solutions the following inequality has. \[ x^{2} + 3x - 1 \leq 0 \]More than three integer solutions.Three integer solutions.Less than three integer solutions.
2010007902 Level: BFor an integer variable \(x\), find the solution set of the following quadratic inequality. \[ 2x^{2} +5x - 12 < 0 \]\(\{ -3,-2,-1,0,1\}\)\(\{-4, -3,-2,-1,0,1\}\)\(\{-4, -3,-2,-1,0,1,2\}\)\(\{-1,0,1,2,3\}\)
2010007901 Level: BThe solution set of one of the following inequalities is \( \left( -\infty, -2\right) \cup \left( 5, \infty \right) \). Identify this inequality.\(x^{2} - 3x -10 > 0\)\(x^{2} + 3x -10 > 0\)\(x^{2} - 3x -10 < 0\)\(x^{2} + 3x -10 < 0\)
2010007705 Level: BFind the solution of the inequality. \[ \sqrt{-x^2+x+2}\geq 4 \]\(x\in\emptyset\)\(x\in [ -3,4]\)\(x\in\mathbb{R}\)\(x\in [ -1,2]\)
2010007605 Level: BFor \(n\in \mathbb{N}\), the difference \(\left({n+1\above 0.0pt n} \right) -\left ({ n+1\above 0.0pt n+1}\right)\) equals to:\(n\)\(0\)\(n+1\)\(2(n+1)\)
2010007604 Level: BThe sum \(\left({19\above 0.0pt 6} \right) +\left ({19\above 0.0pt 7} \right)\) equals to:\(\left({20\above 0.0pt 7} \right)\)\(\left({20\above 0.0pt 6} \right)\)\(\left({19\above 0.0pt 8} \right)\)\(\left({38\above 0.0pt 13} \right)\)
2010007503 Level: BThe number \( 2\cdot6\cdot11 \) has exactly:twelve positive integer divisorssix positive integer divisorsfour positive integer divisorsten positive integer divisors
2010007502 Level: BThe number \( 3\cdot4\cdot11 \) has exactly:twelve positive integer divisorssix positive integer divisorsfour positive integer divisorsten positive integer divisors
2010007501 Level: BThe number \( 3\cdot7\cdot13 \) has exactly:eight positive integer divisorssix positive integer divisorsthree positive integer divisorsfive positive integer divisors
2010007305 Level: BOne side of a rectangle is \(40\, \%\) longer than the other. The length of the diagonal is \(\sqrt{666}\,\mathrm{cm}\). Find the area of the rectangle.\(315\, \mathrm{cm}^2\)\(777\, \mathrm{cm}^2\)\(140\, \mathrm{cm}^2\)\(135\, \mathrm{cm}^2\)