B

9000031208

Level: 
B
Find the polar form of the complex number \(z = -3 + 3\mathrm{i}\).
\(3\sqrt{2}\left (\cos \frac{3\pi } {4} + \mathrm{i}\sin \frac{3\pi } {4}\right )\)
\(3\left (\cos \frac{\pi }{4} + \mathrm{i}\sin \frac{\pi }{4}\right )\)
\(3\left (\cos \frac{5\pi } {4} + \mathrm{i}\sin \frac{5\pi } {4}\right )\)
\(3\sqrt{2}\left (\cos \frac{7\pi } {4} + \mathrm{i}\sin \frac{7\pi } {4}\right )\)

9000026409

Level: 
B
Consider the following equation. \[ |2x - 4| = 5x - 7 \] Solving the equation on the intervals where it is possible to evaluate the absolute value we get equations on partial subintervals as follows. \[\begin{aligned} \text{for }x &\in (-\infty ;2)\colon &\text{for }x &\in [ 2;\infty )\colon & & & & \\ - 2x + 4 & = 5x - 7 &2x - 4 & = 5x - 7 & & & & \\ - 7x & = -11 & - 3x & = -3 & & & & \\x & = \frac{11} {7} &x & = 1 & & & & \end{aligned}\] Find the solution set of the original equation.
\(\left \{\frac{11} {7} \right \}\)
\(\left \{\frac{11} {7} ;1\right \}\)
\(\left \{1\right \}\)
\(\emptyset \)