9000072707
Level:
B
We are given seven consecutive terms of an arithmetic sequence. Find
\(x\).
\[
100\, ,\ a\, ,\ b\, ,\ x\, ,\ c\, ,\ d\, ,\ 0
\]
\(x = 50\)
\(x = 60\)
\(x = 40\)
\(x = 51\)
B
9000072810
Level:
B
The following numbers form a geometric sequence. Find
\(x\).
\[
x\, ,\ 2\cdot 3\, ,\ 3\cdot 4
\]
\(1\cdot 3\)
\(1\cdot 1\)
\(1\cdot 2\)
\(1\cdot 4\)
9000073003
Level:
B
Consider a geometric sequence \((a_{n})_{n=1}^{\infty }\).
Let \(q\) be the quotient
and \(s_{n}\) be the sum
of the first \(n\)
terms. Given \(a_{1} = 1\),
\(a_{3} = 4\) and
\(a_{2} > 0\), find
the sum of the first four terms of the sequence.
\(s_{4} = 15\)
\(s_{4} = -5\)
\(s_{4} = 14\)
\(s_{4} = 8\)
9000072709
Level:
B
We are given seven consecutive terms of an arithmetic sequence. Find
\(x\).
\[
x,\ 1,\ a,\ b,\ c,\ d,\ \frac12
\]
\(x = 1.1\)
\(x = 1.5\)
\(x = -0.5\)
\(x = 2\)
9000073004
Level:
B
Consider a geometric sequence \((a_{n})_{n=1}^{\infty }\).
Let \(q\) be the quotient
and \(s_{n}\) be the sum
of the first \(n\)
terms. Given \(a_{1} = 1\),
\(a_{3} = 4\) and
\(a_{2} < 0\), find
the sum of the first four terms of the sequence.
\(s_{4} = -5\)
\(s_{4} = 15\)
\(s_{4} = 14\)
\(s_{4} = 8\)
9000072802
Level:
B
The following numbers form a geometric sequence. Find
\(x\).
\[
100\, ,\ a\, ,\ 1\, ,\ b\, ,\ x
\]
\(0.01\)
\(- 100\)
\(0.1\)
\(- 10\)
9000072710
Level:
B
We are given seven consecutive terms of an arithmetic sequence. Find
\(x\).
\[
\frac{4}
{5}\, ,\ a\, ,\ b\, ,\ 0\, ,\ c\, ,\ d\, ,\ x
\]
\(x = -\frac{4}
{5}\)
\(x = \frac{5}
{4}\)
\(x = -\frac{5}
{4}\)
\(x = -\frac{8}
{5}\)
9000072809
Level:
B
The following numbers form a geometric sequence. Find
\(x\).
\[
1\, ,\ a\, ,\ x\, ,\ -1
\]
\(1\)
\(-\frac{1}
{3}\)
\(0\)
\(-\frac{2}
{3}\)
9000072803
Level:
B
The following numbers form a geometric sequence. The last term satisfies
\(a > 0\). Find
\(x\).
\[
1\, ,\ x\, ,\ 2\, ,\ a
\]
\(\sqrt{2}\)
\(-\sqrt{2}\)
\(1.5\)
\(- 1.5\)
9000073401
Level:
B
In the following list identify the expression which equals
\(3.3\overline{12}\).
\(3.3 +\sum _{ n=1}^{\infty }12\cdot 10^{-2n-1}\)
\(3 +\sum _{ n=1}^{\infty }312\cdot 10^{-2n-1}\)
\(3 +\sum _{ n=1}^{\infty }312\cdot 10^{-3n}\)
\(3.3 +\sum _{ n=1}^{\infty }12\cdot 10^{-3n}\)