B

1103025306

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 6\,\mathrm{cm} \). The height of the pyramid is \( 3\sqrt2\,\mathrm{cm} \). Find the distance between the point \( A \) and the line \( BV \) (see the picture).
\( 3\sqrt3\,\mathrm{cm} \)
\( 3\sqrt2\,\mathrm{cm} \)
\( \frac32\sqrt3\,\mathrm{cm} \)
\( 3\sqrt6\,\mathrm{cm} \)

1103025305

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 4\,\mathrm{cm} \). The height of the pyramid is \( 6\,\mathrm{cm} \). Find the distance between the point \( A \) and the point \( S_{VC} \), where \( S_{VC} \) is the midpoint of the edge \( VC \).
\( 3\sqrt{3}\,\mathrm{cm} \)
\( 4\sqrt{3}\,\mathrm{cm} \)
\( \sqrt{10}\,\mathrm{cm} \)
\( 3\sqrt{10}\,\mathrm{cm} \)

1103025304

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 8\,\mathrm{cm} \). The height of the pyramid is \( 9\,\mathrm{cm} \). Find the distance between the line \( S_{VA}S_{VD} \) and the line \( BC \). The points $S_{VA}$ and $S_{VD}$ are the midpoints of $VA$ and $VD$, respectively.
\( 7.5\,\mathrm{cm} \)
\( \frac23\sqrt{97}\,\mathrm{cm} \)
\( \frac{\sqrt{97}}2\,\mathrm{cm} \)
\( \sqrt{17}\,\mathrm{cm} \)

1103025303

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 6\,\mathrm{cm} \). The height of the pyramid is \( 4\,\mathrm{cm} \). Find the distance between the line \( S_{VA}S_{VC} \) and the line \( AC \). The points $S_{VA}$ and $S_{VC}$ are the midpoints of $VA$ and $VC$, respectively.
\( 2\,\mathrm{cm} \)
\( 2.5\,\mathrm{cm} \)
\( \frac{\sqrt{52}}2\,\mathrm{cm} \)
\( 4\,\mathrm{cm} \)

1103025302

Level: 
B
The base \( ABCD \) of a square pyramid \( ABCDV \) has an edge of \( 6\,\mathrm{cm} \). The height of the pyramid is \( 4\,\mathrm{cm} \). Find the distance between the line \( S_{VB}S_{VC}\) and the line \( BC \). The points $S_{VB}$ and $S_{VC}$ are the midpoints of $VB$ and $VC$, respectively.
\( 2.5\,\mathrm{cm} \)
\( 2\,\mathrm{cm} \)
\( \frac{\sqrt{52}}2\,\mathrm{cm} \)
\( \frac{25}2\,\mathrm{cm} \)