2010013201

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2010013201
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Určte komplexné korene danej kvadratickej rovnice. \[ 3x^2 + 8 = 0 \]
\( x_1=-\frac{2\sqrt{6}}3\mathrm{i},\ x_2=\frac{2\sqrt{6}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{6}}3\mathrm{i},\ x_2=\frac{\sqrt{6}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{12}}3\mathrm{i},\ x_2=\frac{\sqrt{12}}3\mathrm{i} \)
\( x_1=-\frac{\sqrt{6}}6\mathrm{i},\ x_2=\frac{\sqrt{6}}6\mathrm{i} \)