Level:
Project ID:
9000153702
Accepted:
1
Clonable:
0
Easy:
1
The picture shows a square pyramid. The side of a base square is
\(a = 4\; \mathrm{cm}\) and the height of
the pyramid is \(v = 6\; \mathrm{cm}\).
Find the angle \(\varphi \).
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{6}
{2\sqrt{2}}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 64^{\circ }46^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{6}
{2}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 71^{\circ }34^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \frac{\varphi }
{2} = \frac{2}
{6}\mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 36^{\circ }52^{\prime}\)
\(\mathop{\mathrm{tg}}\nolimits \varphi = \frac{2\sqrt{10}}
{2} \mathrel{\implies }\varphi \mathop{\mathop{\doteq }}\nolimits 72^{\circ }27^{\prime}\)