Level:
Project ID:
9000128802
Accepted:
1
Clonable:
0
Easy:
0
The base \(ABCD\) of a square
pyramid \(ABCDV \) has side
\(6\, \mathrm{cm}\). The height of the
pyramid is \(4\, \mathrm{cm}\). The point
\(M\) is the middle of the
side \(CV \). Find the distance
between the point \(M\)
and the line \(BC\).
\(\frac{5}
{2}\, \mathrm{cm}\)
\(\frac{\sqrt{34}}
{2} \, \mathrm{cm}\)
\(\frac{\sqrt{7}}
{2} \, \mathrm{cm}\)