9000065610

Level: 
Project ID: 
9000065610
Accepted: 
1
Clonable: 
0
Easy: 
1
Using definite integral find the area of the triangle defined by the following three inequalities \[ \begin{aligned}y& > 0, & \\y& < x + 3, \\y& < 3 - x. \\ \end{aligned} \]
\(\int _{-3}^{0}(x + 3)\, \mathrm{d}x +\int _{ 0}^{3}(3 - x)\, \mathrm{d}x\)
\(\int _{0}^{3}(x + 3)\, \mathrm{d}x\)
\(\int _{-3}^{3}(3 - x)\, \mathrm{d}x\)
\(\int _{-3}^{0}(3 - x)\, \mathrm{d}x +\int _{ 0}^{3}(x + 3)\, \mathrm{d}x\)