Level:
Project ID:
9000021806
Source Problem:
Accepted:
1
Clonable:
1
Easy:
0
Solve the following inequality.
\[
\frac{1 - 3x}
{x + 2} \geq 0
\]
\(x\in \left (-2; \frac{1}
{3}\right ] \)
\(x\in \left [ \frac{1}
{3};\infty \right )\)
\(x\in \left (\frac{1}
{3};\infty \right )\)
\(x\in (-\infty ;-2)\cup \left [ \frac{1}
{3};\infty \right )\)