9000021806 | math4u.vsb.cz

SubArea:

Rational equations and inequalities

Level:

Project ID:

9000021806

Source Problem:

Accepted:

1

Clonable:

1

Easy:

0

Solve the following inequality.

\frac{1 - 3 x}{x + 2} \geq 0

x \in (- 2; \frac{1}{3}]

x \in [\frac{1}{3}; \infty)

x \in (\frac{1}{3}; \infty)

x \in (- \infty; - 2) \cup [\frac{1}{3}; \infty)