Converting Complex Numbers to Polar Form

Submitted by vladimir.arzt on Sun, 08/25/2024 - 14:26

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7100000054

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Question:

Pair each complex number with its corresponding polar form.

Question 1:

- i \cdot \sqrt{2}

Answer 1:

\sqrt{2} \cdot (\cos 270^{\circ} + i \cdot \sin 270^{\circ})

Question 2:

\frac{\sqrt{6}}{2} - \frac{\sqrt{2}}{2} \cdot i

Answer 2:

\sqrt{2} \cdot (\cos \frac{11 π}{6} + i \cdot \sin \frac{11 π}{6})

Question 3:

- \sqrt{2}

Answer 3:

\sqrt{2} \cdot (\cos π + i \cdot \sin π)

Question 4:

- \frac{\sqrt{6}}{2} - \frac{\sqrt{2}}{2} \cdot i

Answer 4:

\sqrt{2} \cdot (\cos 210^{\circ} + i \cdot \sin 210^{\circ})

Question 5:

1 - \sqrt{3} \cdot i

Answer 5:

$2 \cdot (\cos \frac{5 π}{3} + i \cdot \sin \frac{5 π}{3})$

Question 6:

- 1 + \sqrt{3} \cdot i

Answer 6:

2 \cdot (\cos 120^{\circ} + i \cdot \sin 120^{\circ})

Question 7:

\cos π + 2 \cdot i \cdot \sin \frac{4 π}{3}

Answer 7:

2 \cdot (\cos 240^{\circ} + i \cdot \sin 240^{\circ})

Question 8:

- 2

Answer 8:

2 \cdot (\cos 180^{\circ} + i \cdot \sin 180^{\circ})

Question 9:

\cos 0 + 2 \cdot i \cdot \sin \frac{2 π}{3}

Answer 9:

2 \cdot (\cos 60^{\circ} + i \cdot \sin 60^{\circ})

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