Project ID:
6000000069
Accepted:
Type:
Layout:
Question:
Match each given vertex form equation of a parabola with its diagram.
Questions Title:
Graphs:
Answers Title:
Equations:
Question 1:
{\obrA}
Question 1 Image:
Answer 1:
$x^2=4(y-1)$
Question 2:
{\obrB}
Question 2 Image:
Answer 2:
$x^2=4(y+1)$
Question 3:
{\obrC}
Question 3 Image:
Answer 3:
$y^2=4(x-1)$
Question 4:
{\obrD}
Question 4 Image:
Answer 4:
$y^2=4(x+1)$
Tex:
% tiket 32387
\NastavOD{4}
\def\obrA{\obrMsr[x=0.4cm,y=0.4cm]{-4}{4}{-2}6
{
\footnotesize
\obrClip
\obrOsaX
\obrOsaY[below right]
\obrPopisX[below]{-2,2}
\obrPopisY[below left]{1}
\obrZnackyY{2}
\draw[dashed] (-2,0) -- (-2,2) -- (2,2) -- (2,0);
\obrFce{(\x)^2/4+1}
\fill[blue] (-2,2) circle (2pt);
\fill[blue] (2,2) circle (2pt);
\draw (4,0) node [above left, xshift=3pt]{$x=d$};
\draw (0,2) node [above left]{$F$};
}}
\def\obrB{\obrMsr[x=0.4cm,y=0.4cm]{-4}{4}{-3}5
{
\footnotesize
\obrClip
\obrOsaX[above left]
\obrOsaY[below right]
\obrPopisX[below right]{2}
\obrPopisX[below left]{-2}
\obrPopisY[below left]{-1,-2}
\obrZnackyY{0}
\draw (-4,-2) -- (4,-2) node [above left]{$d$};
\obrFce{(\x)^2/4-1}
\draw (0,0) node [above left]{$F$};
}}
\def\obrC{\obrMsr[x=0.4cm,y=0.4cm]{-2}{6}{-4}4
{
\footnotesize
\obrClip
\obrOsaX[above left]
\obrOsaY
\obrPopisX[below left]{0,1}
\obrPopisY[left]{-2,2}
\obrZnackyX{2}
\draw[dashed] (0,-2) -- (2,-2) -- (2,2) -- (0,2);
\obrFce[domain=1:6]{(4*((\x)-1))^(1/2)}
\obrFce[domain=1:6]{-(4*((\x)-1))^(1/2)}
\fill[blue] (2,-2) circle (2pt);
\fill[blue] (2,2) circle (2pt);
\draw (0,4) node [below right]{$y=d$};
\draw (2,0) node [above right]{$F$};
}}
\def\obrD{\obrMsr[x=0.4cm,y=0.4cm]{-3}{5}{-4}4
{
\footnotesize
\obrClip
\obrOsaX[above left]
\obrOsaY[below right]
\obrPopisY[above left]{2}
\obrPopisY[below left]{-2}
\obrZnackyX{0}
\draw (-1,0) node [below left, xshift=3pt, yshift=-2pt]{$-1$};
\draw (-2,0) node [below left, xshift=2pt, yshift=-2pt]{$-2$};
\draw (-2,-4) -- (-2,4) node [below right]{$d$};
\obrFce[domain=-1:5]{(4*((\x)+1))^(1/2)}
\obrFce[domain=-1:5]{-(4*((\x)+1))^(1/2)}
\draw (0,0) node [above right]{$F$};
}}