2010012002 | math4u.vsb.cz

SubArea:

Trigonometric equations and inequalities

Level:

Project ID:

2010012002

Source Problem:

Accepted:

0

Clonable:

1

Easy:

0

Solve

\cos^{2} x = \sqrt{2} \cos x

for

x

, where

x \in R

.

x \in ⋃_{k \in Z} {\frac{π}{2} + k π}

x \in ⋃_{k \in Z} {\frac{π}{4} + k π; \frac{π}{2} + k π}

x \in ⋃_{k \in Z} {\frac{π}{4} + k π}

x \in \emptyset