SubArea: Space geometryLevel: CProject ID: 2010008709Source Problem: 2010008710Accepted: 0Clonable: 1Easy: 0Reflect the point P=[4;−8;7] across the plane σ:3x−2y+4z+2=0. Hint: The line PP′ is perpendicular to the plane σ (see the picture).P′=[−8;0;−9]P′=[−2;−4;−1]P′=[10;−12;15]P′=[16;−16;23]