Level:
Project ID:
2000004202
Accepted:
0
Clonable:
0
Easy:
1
On the interval \( (-\frac{\pi}{2};\frac{\pi}{2})\), simplify the expression \(\frac{\sin 2x}{1 -\sin^2 x}\).
\( 2\ \mathrm{tg}\,x\)
\(\mathrm{tg}\,x\)
\( \mathrm{tg}^2\,x\)
\( 1-\mathrm{tg}\,x\)