1103077011 | math4u.vsb.cz

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1103077011

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Consider a triangle

A B C

with

a = 1 cm

and

b = \sqrt{3} cm

. The angle opposite the longer side is double the angle opposite the shorter side. Find the area of the triangle.

\frac{\sqrt{3}}{2} {cm}^{2}

2 \sqrt{3} {cm}^{2}

\sqrt{3} {cm}^{2}

\frac{\sqrt{3}}{4} {cm}^{2}