1003107303 | math4u.vsb.cz

SubArea:

Introduction to sequences

Level:

Project ID:

1003107303

Source Problem:

Accepted:

1

Clonable:

1

Easy:

0

We are given the sequence

{(2^{2 - n})}_{n = 1}^{\infty}

. Find the recursive formula of such sequence.

a_{1} = 2; a_{n + 1} = a_{n} \cdot \frac{1}{2}, n \in N

a_{1} = 2; a_{n + 1} = a_{n} \cdot 2, n \in N

a_{1} = 2; a_{n + 1} = a_{n} \cdot 2^{n}, n \in N

a_{1} = 2; a_{n + 1} = a_{n} \cdot \frac{1}{2^{n}}, n \in N