1003029203 | math4u.vsb.cz

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Three dice are thrown together. Find the probability that three different outcomes are rolled. Results are rounded to two decimal places.

\frac{(\binom{6}{1}) \cdot (\binom{5}{1}) \cdot (\binom{4}{1})}{6^{3}} = 0.56

\frac{(\binom{6}{1}) + (\binom{5}{1}) + (\binom{4}{1})}{6^{3}} = 0.07

\frac{(\binom{6}{6}) \cdot (\binom{6}{5}) \cdot (\binom{6}{4})}{6^{3}} = 0.42

\frac{(\binom{6}{6}) + (\binom{6}{5}) + (\binom{6}{4})}{6^{3}} = 0.10