Derivace funkce

9000063302

Část: 
B
Derivace funkce \(f\colon y = (3x^{2} + 2)^{3}\) je rovna:
\(f'(x) = 18x(3x^{2} + 2)^{2},\ x\in \mathbb{R}\)
\(f'(x) = 18x(3x^{2} + 2),\ x\in \mathbb{R}\)
\(f'(x) = 18x^{2}(3x + 2)^{2},\ x\in \mathbb{R}\)
\(f'(x) = 108x^{2},\ x\in \mathbb{R}\)

9000063303

Část: 
C
Derivace funkce \(f\colon y = \sqrt{\sin x}\) je rovna:
\(f'(x) = \frac{\cos x} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ;\pi + 2k\pi \right )\)
\(f'(x) = \frac{\sin x} {2\sqrt{\cos x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ; \frac{\pi } {2} + 2k\pi \right )\)
\(f'(x) = \frac{1} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left (2k\pi ;\pi + 2k\pi \right )\)
\(f'(x) = \frac{\cos x} {2\sqrt{\sin x}},\ x\in \mathop{\mathop{\bigcup }}\nolimits _{k\in \mathbb{Z}}\left \langle 2k\pi ; \frac{\pi } {2} + 2k\pi \right \rangle \)

9000063101

Část: 
B
Derivace funkce \(f\colon y = \frac{x^{2}-1} {x^{2}+1}\) je rovna:
\(f'(x) = \frac{4x} {(x^{2}+1)^{2}} ,\ x\in \mathbb{R}\)
\(f'(x) = \frac{-4x} {x^{2}+1},\ x\in \mathbb{R}\)
\(f'(x) = \frac{4x^{3}} {(x^{2}+1)^{2}} ,\ x\in \mathbb{R}\)
\(f'(x) = \frac{4x} {x^{2}+1},\ x\in \mathbb{R}\)

9000063103

Část: 
B
Derivace funkce \(f\colon y = \frac{x^{2}-x} {x+1} \) je rovna:
\(f'(x) = \frac{x^{2}+2x-1} {(x+1)^{2}} ,\ x\neq - 1\)
\(f'(x) = 2x - 1,\ x\neq - 1\)
\(f'(x) = \frac{x^{2}+2x-1} {(x+1)^{2}} ,\ x\neq 0\)
\(f'(x) = \frac{2x} {(x^{2}+1)^{2}} ,\ x\neq 0\)

9000063104

Část: 
B
Derivace funkce \(f\colon y = \frac{\sin x} {\sin x-\cos x}\) je rovna:
\(f'(x) = \frac{-1} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\sin ^{2}x-\cos ^{2}x} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\sin x(\cos x+1)} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)
\(f'(x) = \frac{\cos ^{2}x-\sin ^{2}x} {(\sin x-\cos x)^{2}} ,\ x\neq \frac{\pi }{4} + k\pi ;k\in \mathbb{Z}\)

9000063107

Část: 
B
Derivace funkce \(f\colon y =\cos x(1 +\sin x)\) je rovna:
\(f'(x) =\cos ^{2}x -\sin ^{2}x -\sin x,\ x\in \mathbb{R}\)
\(f'(x) = -\sin x\cos x,\ x\in \mathbb{R}\)
\(f'(x) =\cos x,\ x\in \mathbb{R}\)
\(f'(x) =\sin x +\sin ^{2}x -\cos ^{2}x,\ x\in \mathbb{R}\)