Level:
Project ID:
2010017802
Source Problem:
Accepted:
0
Clonable:
1
Easy:
0
Find the tangent to the graph of the function
\(f(x) = x^{2} - 6x + 1\) perpendicular
to the line \(x -2y + 4 = 0\).
\(2x + y +3 = 0\)
\(-2x - y - 1= 0\)
\(4x +2y - 1= 0\)
\(-4x - 2y +3 = 0\)