SubArea: Exponential equations and inequalitiesLevel: BProject ID: 9000003705Accepted: 1Clonable: 1Easy: 0Solve the following exponential equation. 32x−12⋅3x+27=0x1=1; x2=2x1=3; x2=9x1=−1; x2=−2x1=−3; x2=−9
